The perimeter of a rectangle of a rectangular field is 76 ft. the length is 12 ft longer than the width. find the fields dimensions

The length is 25 and the width is 13. (25,13)

Step-by-step explanation:

the formula for perimeter is l+l+w+w=76 or 2l+2w=76

and since we know that the length is 12 more than the width, we can create an equation. w+12=l (-l+w=-12)

solve with elimination method:

2l+2w=76

2(-l+w=-12)

2l+2w=76

-2l+2w=-24

4w=52

w=13

Now that we know w=13, add 12 to the width and you get your width (25)

You can check this with the formula 2l+2w=76

2(25)+2(13)=76

50+26=76

and

w+12=l

13+12=25

Hope this helps!

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.