You conduct an experiment where you roll a die and record the results. you roll the die 1,230 times, and the results are shown in the table below: result frequency1 2452 1723 2194 2015 1376 256what is the experimental probability of rolling a 1 on your next roll? a. 0.1667 b. 0.1992 c. 0.245 d. 0.3275part b. what is the theoretical probability of rolling a 3 on your next roll? a. 0.167 b. 0.178 c. 0.245 d. 0.333the probability of an event is 2/7what are the odds of the same event? a. 7/9 b. 5/7 c. 2/9 d. 2/5if i could get some that'd be greattt

The experimental probability of rolling a 1 is 0.1992 (B).  The Theoretical probability of rolling a 3 on your next roll is 0.167 (A).  The last question is a bit redundant, but I think they are looking for 5/7 (B).

Step-by-step explanation:

For this question, it is important to understand the difference between experimental probabilty and theoretical probability.  Experimental is the results that you actually get from performing the experiment or process, while theoretical is what you should get from peforming the same experiment.  In this case, they give us the actual, or experimental, results.  So, for Part A, we need to use these results to find the experimental probability of rolling 1, which is 245/1230, or 0.1667.  However, for Part B, they are asking for the theoretical probability, which is what should happen.  On a six-sided number cube (die), you only have 6 outcomes one of which is the number 3.  So, the theoretical probablity of rolling a 3 is 1/6, or 0.1667.  Lastly, if the probability of an event happening is 2/7, the probability that the event will NOT happen is 5/7.  

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

stop cheating

step-by-step explanation: