What is the equation of a line that is perpendicular to 4x-3y=12 and passes through (-8,1)?

y=-(3/4)x-5

Step-by-step explanation:

First we must write our equation in slope intercept form:

Where m is slope and b is the y-intercept.

Now we will find a line that is perpendicular to

To do this we will get the negative inverse of our original slope which is 4/3 and the negative inverse is: .

Now we must determine our y-intercept for the perpendicular line by using the slope calculated above and plugging it in to the following equation:

Where m is the slope, x1 = -8 and y1=1 and so:

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation: