Liam volunteers to plan the event. the first month, he volunteered for x hours. the next month he volunteered for 1 2/3 times as many hours as he had the first month. if he volunteered for a total of 40 hours, how many hours did he volunteer during the first month? write an equation to represent the situation and solve.

Hours in first month = 8

Step-by-step explanation:

AS it is given

He volunteered fr the first month = x hours

He volunteered for the second  month = 12/3 times of first month

which will be =

Total Hours volunteered = 40 hours

Now according to the given conditions

Volunteered first month + volunteered second month = total

putting this gives

x + = 40

as 12/3 = 4 so

it becomes

x + 4x = 40    

solcing it will gives

5x = 40

x = 40/5

x = 8

So Numbers of hours worked in first month are 8

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

i think it would be c

mark brainliest if im right

step-by-step explanation: