In a certain algebra 2 class of 29 students, 5 of them play basketball and 16 of them play baseball. there are 10 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

ANSWER


EXPLANATION
Let the number who plays both games be

Then those who play only basketball


and those who play only baseball


We were given that 10 students play neither sports.

We can then write the following equation,



This implies that,



This simplifies to,



This gives us,



Therefore the number of students play both basketball and baseball is 2.

The probability that a student chosen from the class plays both basketball and baseball ball

2,4,5,8,10 are divisible by 40

The second and fourth answer are correct