Asix-sided die with sides labeled 1 through 6 will be rolled once. each number is equally likely to be rolled. what is the probability of rolling a number greater than 2? write your answer as a fraction.

2/3

Step-by-step explanation:

Given that a six sided die with sides labelled with numbers 1,2,3,4,5 and 6 is rolled once.

Since die is said to be equally likely for each number, die is unbiased

P(1) = P(2)=...=P(6) = 1/6

For a number greater than 2, we must not include 2 and hence numbers can be 3 or 4 or 5 or 6

Probability of rolling a number >2 = Probability of rolling 3 or 4 or 5 or 6

= P(3)+P(4)+P(5)+P(6)

= 1/6+1/6+1/6+1/6

=4/6

=2/3

Required probability = 2/3

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are