Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool. if it takes 30 minutes for the larger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on its own? do not do any rounding.

60 minutes for the larger hose to fill the swimming pool by itself

Step-by-step explanation:

It is given that,

Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.

takes 30 minutes for the larger hose to fill the swimming pool by itself

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

To find LCM of 20 and 30

LCM (20, 30) = 60

To find the efficiency

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

x = 60/30 =2

x + y = 60 /20 = 3

Therefore efficiency of y = (x + y) - x =3 - 2 = 1

so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.