75 points to the first person who the dot plot below shows the number of different types of trees in sean's garden: a straight line is shown with 4 equidistant marks. the first mark is labeled redbud, the second mark is labeled magnolia, the third mark is labeled snowbell, and the fourth mark is labeled maple. the first mark has 2 dots, the second mark has 3 dots, the third mark has 1 dot, and the fourth mark has 4 dots. below the line is written number of trees. which table shows the data displayed in the dot plot? garden trees number redbud 4 magnolia 1 snowbell 3 maple 2 garden trees number redbud 1 magnolia 2 snowbell 0 maple 3 garden trees number redbud 2 magnolia 5 snowbell 6 maple 10 garden trees number redbud 2 magnolia 3 snowbell 1 maple 4

Garden TreesNumber

Redbud2

Magnolia3

Snowbell1

Maple4

Step-by-step explanation:

If the first mark is labeled Redbud and has 2 dots then it has 2 trees.

If the second mark is labeled Mangolia and has 3 dots then it has 3 trees.

If the third mark is labeled Snowbell and has 1 dot then it has 1 tree.

If the fourth mark is labeled Maple and has 4 dots then it has 4 trees.

2nd one in the first row is correct

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)