Aline passes through the points (-10,-5) and (20,10) what is the equation of the line a. y=5x b. y=2x c.1/2 x dy=1/5 x

C. y = ½x

Step-by-step explanation:

Step 1. Find the slope of the line

The general equation for a straight line is

y = mx + b

The slope m is

m =(y₂ -y₁)/(x₂/x₁)

Your points are (-10, -5) and (20, 10).

m = [10 – (-5)]/[20 – (-10)]     Remove inner parentheses

m  = (10+5)/(20 + 10)

m = 15/30

m = ½

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Step 2. Find the equation of the line

Substitute the point (20, 10) into the general equation.

10 = ½×20 + b

10 = 10 + b

b = 0

The equation of the line is y = ½x.

The graph shows your line passing through your two points with a slope

m = ½ and a y-intercept at (0, 0).

i dont know

step-by-step explanation:

answer: 1 and 3

step-by-step explanation: