50 points answer let f(x)=8(3^)x−2+2 . the graph of f(x) is stretched vertically by a factor of 3 to form the graph of g(x) . what is the equation of g(x) ? function f is an exponential function. x −2 0 2 4 6 f(x) 1/64 1/16 14 1 4 by what factor does the output value increase as each input value increases by 1? enter your answer in the box.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

i agree because i see the other persons thinking is clear

could you provide figure.