Use the elimination method to solve the system of equation. choose the correct ordered pair. 5x=3y+31 2x=3y+25

B. (2, 7)

Step-by-step explanation:

(1)  5x + 3y = 31

(2) 2x + 3y = 25     Subtract (2) from (1)

            3x = 6        Divide each side by 3

              x = 2        Substitute in (2)

     4 + 3y = 25       Subtract 4 from each side

           3y = 21        Divide each side by 3

             y = 7

The solution is (2, 7).

Check:

(1)   5×2 + 3×7 = 31

          10 + 21 = 31

                 31 = 31

(2) 2×2 + 3×7 = 25

           4 + 21 = 25

                25 = 25

B Ordered pair  ( 2 ,7).

Step-by-step explanation:

Given  : 5x = 3y+31  and  2x = 3y+25.

To find : use the elimination method to solve the system of equation.

Solution : We have given that

5x +3y = 31 (1)

2x +3y = 25(2)

On subtracting equation (2) from (1)

5x + 3y = 31

(-)2x +(-)3y = (-)25

3x +0  = 6

3x =6

On dividing by 3 both sides

x = 2.

Now plugging the value of x = 2 in equation (1)

5 (2)+ 3y = 31

10 +3y = 31

On subtracting both sides by 10

3y = 31 -10

3y =  21

On dividing by 3 both sides

y = 7

Ordered pair  ( 2 ,7).

Therefore, B Ordered pair  ( 2 ,7).

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.