15 need ! write an equation in point-slope form of a line which is perpendicular to x + 5y = 5 and passes through the point (10, -1).

y + 1 = 5(x - 10)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the t-intercept )

rearrange x + 5y = 5 into this form ( subtract x from both sides )

5y = - x + 5 ( divide all terms by 5 )

y = - x + 1 ← in slope- intercept form

with slope m = -

given a line with slope m then the slope of a line perpendicular to it is

= - = - = 5

using m = 5 and (a, b) = (10, - 1), then

y + 1 = 5(x - 10) ← in point- slope form

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