Which table represents a linear function?

Table 4 represents the linear function.

Step-by-step explanation:

For table 1.

y = mx + c

m = (y-y')/(x-x') = (2-1)/1-0 = 1

y = x +c

Since point(2, 4) lies on the the line

4 = 2 + c

c = 2

y = x + 2

If third point(3, 8) passes through the line then it's a linear function.

8 = 3 + 2 = 5

which is not true therefore its nor linear.

For table 2

y = mx + c

passes through origin (0,0)

so c =0

m = (0-1)/(0-1) =1

y = x is the equation

But points 2 and 3 of the table don't follow the equation so function is non linear.

For table 3

y = mx + c

passes through (0,0)

so c  =0

m = (1-0)/(1-0) = 1

y = x will the equation but points 3 and 4 don't pass through this line so function is non linear.

For 4th table

y = mx + c

m = (1-3)/(0-1) = 2

passe through (2, 5)

5 = 2.2 + c

c = 1

y = 2x + 1

since Fourth point (3, 7) satisfy the function.

7 = 3.2 + 1 = 7

Therefore this table represents a linear function.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

stop using this to cheat on home work

step-by-step explanation:

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