99 points show your work q+b=13. when b+3=0

When Q = 16 then B + 3 = 0

Step-by-step explanation:

When Q = 16 then B + 3 = 0

Step-by-step explanation:

It is given that

Q + B = 13

To find the value of B

We know that Q + B = 13

From this we get value of B

B = 13 - Q

To find the value of Q

We have to find  when B + 3 =0

13 - Q + 3 =0  

Q = 16

When Q =16 then

B + 3 =0

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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