How many different arrangements of 3 letters can be formed if the first letter must be w or k (repeats of letters are allowed)?

Total 1352 different arrangements can be formed.

Step-by-step explanation:

Total number of letters is 26 (a to z).

We need to find the arrangements of 3 letters

It is given that the first letter must be w or k and repetition of letters are allowed.

Since first letter can be w or k, therefore the possibilities for first letter is 2.

Repetition of letters are allowed and any letter can be formed in place of second and third letter.

So, the possibilities for second letter is 26 and possibilities for third letter is 26.

Total possibilities of arrangements of 3 letters is

Therefore total 1352 different arrangements can be formed.

answer: y=4000x+14000

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~