Nis the sum of three consecutive primes and is also the product of two 2-digit primes, what is the least possible value of n

Hello from MrBillDoesMath!

  N = 143

Discussion:

This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers:  11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of  3 consecutive primes.   I went back to my list of primes,  added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on  43, 47, and 53!

43 + 47 + 53 =  143 !

Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.

Thank you,

MrB

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.