Which is a solution of the equation? y = -2x + 4 a. (-1, 3) b. (-2, 8) c. (0, 1) d. (4, 2) show your work! god bless

b

Step-by-step explanation:

to determine which point is a solution, substitute the x-coordinate of the point into the equation and if the value is equal to the y-coordinate of the point then it is a solution.

(a) (- 1, 3)

y = (- 2 × - 1) + 4 = 2 + 4 = 6 ≠ 3 ⇒(-1, 3) is not a solution

(b) (- 2, 8)

y = (- 2 × - 2) + 4 = 4 + 4 = 8 ⇒ (- 2, 8) is a solution

(c) (0, 1)

y = 0 + 4 = 4 ≠ 1 ⇒ (0, 1) is not a solution

(d) (4, 2)

y = (2 × 4) + 4 = 8 + 4 = 12 ≠ 2 ⇒ (4, 2) is not a solution

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}