Mathematics, 29.06.2019 12:00 leonthegreat24

How long a 30-pound bag of dog food will last. he has 3 big dogs, and each dog eats 2 pounds of food in one day.

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Answer from: alyssa0888

5 days.

Step-by-step explanation:

We are told that one person has 3 dogs and each dog eats 2 pounds of food in one day.

Let us find amount of food needed for 3 dogs in 1 day by multiplying number of dogs (3) by amount of food eaten by one dog (2 pounds).

$\text{Amount of food eaten by 3 dogs in one day}=3*2\text{ pounds}$

$\text{Amount of food eaten by 3 dogs in one day}=6\text{ pounds}$

Now let us divide 30 by 6 to find the number of days available food will last.

$\text{30 pound of food bag will last}=\frac{30}{6}$

$\text{30 pound of food bag will last}=5$

Therefore, 30-pound bag of dog food will last for 5 days.

Answer from: Quest

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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How long a 30-pound bag of dog food will last. he has 3 big dogs, and each dog eats 2 pounds of food...

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