If g(x) = x^2 + 6x with x ≥ -3, find g ^-1(0). and explain how to get the answer if you can.

0

Step-by-step explanation:

g(x) = x² + 6x   ; x ≥ -3

To find the inverse, swap the x's and y's and solve for "y":

    x = y² + 6y

x + 9 = y² + 6y + 9   add 9 to both sides to create a perfect square

x + 9 = (y + 3)²

= y + 3   take square root of both sides

= y    ; y ≥ -3

g⁻¹(0) =

        =

        = -3 ± 3

        = -3 + 3   ,   -3 - 3

        =     0      ,      -6

since the restriction is: y ≥ -3, then -6 is not valid

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew