What is the slope of the line passing through the points (1, –5) and (4, 1)? a. 2 b. -4/5 c. 5/4 d. –2

A. 2

Step-by-step explanation:

slope = (y2-y1)/ (x2-x1)

  = (1--5)/(4-1)

 = (1+5)/(3)

6/3

=2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%