Which point on the unit circle corresponds to -pi/6 ? )/2, 1/2)(-1/2, (sqrt3)/2)(1/2, -(sqrt3)/2)((sqrt3)/2, -1/2)

(srt(3)/2, -1/2)

Step-by-step explanation:

x = rcos theta

r = 1 on unit circle

x = 1 cos (-pi/6)

x = sqrt(3)/2

y = r sin theta

y =1 sin (-pi/6)=

y = -1/2

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

b. 153 students do not participate in sports and seventy-five 12th graders were surveyed