What is sin θ given (–3, 4) is a point on the terminal side of θ? question 1 options: 3/5-3/54/5-4/5what is cos θ given (–5, –4) is a point on the terminal side of θ? question 2 options: −5√41/√415√41/√41−4√41/√414√41/√41t he line with equation 4b + a = 0 coincides with the terminal side of an angle x in standard position in quadrant iv. what is sin x? question 3 options: −1/4−17/√17√174√17/√17

QUESTION 1-  

QUESTION 2-  

QUESTION3-

Step-by-step explanation:

For Question 1

From the given point(-3,4), we can deduce the following.

The point is in the 2nd quadrant.

The right-angled triangle which is formed has a hypotenuse of length 5 by Pythagoras theorem whrere B=3 and P=4.

The third quadrant are from 90° to 180° in which the angle lie.

so  

For Question 2

From the given point(-4,-5), we can deduce the following.

The point is in the 3rd quadrant.

The right-angled triangle which is formed has a hypotenuse of length   by Pythagoras theorem whrere B=-4 and P=-5.

The third quadrant are from 180° to 270° in which the angle lie.

so  

For Question 3

The line with equation 4b + a = 0 , we can deduce that the value of

slope of line  

Hypotenuse of length by Pythagoras theorem whrere B=4and P=1.

so  .

a

step-by-step explanation:

jml angle lkj & angle mj = lm