What is the solution set of the quadratic inequality x^2+x-2> 0

(-∞, -2) U (1, ∞)

Step-by-step explanation:

    x² + x - 2 > 0

First, find the zeros by setting the equation EQUAL to zero:

   x² + x - 2 = 0

 (x + 2)(x - 1) = 0

x + 2 = 0    x - 1 = 0

  x = -2        x = 1

Next, choose a test point to the left, between, and to the right of the zeros and check to see if the test points are positive (greater than zero)

Left (x = -3):    (-3 + 2)(-3 - 1) = (-)(-) = +

Between (x = 0):   (0 + 2)(0 - 1) = (+)(-) = -

Right (x = 2):   (2 + 2)(2 - 1) = (+)(+) = +

The left and right test points are positive (greater than zero) so the solution is x < -2 and x > 1

Interval Notation: (-∞, -2) U (1, ∞)

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

answer: i'm not sure

step-by-step explanation: