Amerchant has coffee worth $60 a pound that she wishes to mix with 50 pounds of coffee worth $90 a pound to get a mixture that is worth $70 a pound. how many pounds (lb) of the $60 coffee should be used?

Step-by-step explanation:

Alright, lets gets started.

Suppose she mixes x pounds of coffee of $ 60 a pound.

So, the cost of that coffee =

Merchant has 50 pounds of coffee worth $ 90 a pound, hence the cost of this second coffee =

The mixture she get, is worth $ 70 and the weight of this mixture will be

So, the cost of mixture will be =

Addition of both coffees will be equal to the mixture, so

Subtracting 60 x in both sides

Subtracting 3500 in both sides

Dividing 10 in both sides

x = 100 pounds

It means she needs to add 100 pounds of that coffee.  :  Answer

Hope it will help :)

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.