Ahistory class is comprised of 7 female and 10 male students. if the instructor of the class randomly chooses 13 students from the class for an oral exam, what is the probability that 6 female students and 7 male students will be selected? round your answer to 3 decimal places.

0.353

Step-by-step explanation:

We have been given that a history class is comprised of 7 female and 10 male students.        

We will use combinations to solve our problem.  

We can choose 6 female students out of 7 female students in ways.

We can choose 7 male students out of 10 male students in ways.  

So the number of ways that 6 female and 7 males can be chose is: 7*120 = 840.

Now let us find ways in which 13 students can be chosen from 17 students as:        

Now let us substitute our values in probability formula.

Therefore, the probability of selecting 6 female students and 7 male students is 0.353.  

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.