Given the position function s(t), s(t) = t2 + 3t + 1, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 4 seconds. (5 points) 11 m/sec; 2 m/sec2 2 m/sec; 0 m/sec2 11 m/sec; 0 m/sec2 12 m/sec; 2 m/sec2

  11 m/s; 2 m/sec²

Step-by-step explanation:

v(t) = s'(t) = 2t +3

v(4) = 2·4 +3 = 11 . . . m/s

__

a(t) = v'(t) = 2 . . . . m/s²

__

Velocity and acceleration are 11 m/s and 2 m/s².

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.