Write an equation for a line that is parallel to the given line that passes through the given point. explain how you found the equation. y=2x+7; (3,11) show all work plz

Slope-intercept form:

y = mx + b   "m" is the slope, "b" is the y-intercept (the y value when x = 0)

For lines to be parallel, they have to have the SAME slope.

The given line's slope is 2, so the parallel line's slope is also 2.

y = 2x + b

To find "b", plug in the point (3,11) into the equation.

y = 2x + b

11 = 2(3) + b      Multiply 2 and 3

11 = 6 + b      Subtract 6 on both sides

5 = b

y = 2x + 5

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

4x and 6y

im not sure though