Applying the quadratic formula the height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where h0 is the initial height of the object. suppose a small rock dislodges from a ledge that is 255 ft above a canyon floor. solve the equation h = -16t2 + 255 for t, using the quadratic formula to determine the time it takes the rock to reach the canyon floor. a)t ≈ 0.87 s b)t ≈ 4 s c)t= 8.5 s d)t = 16 s

B

Step-by-step explanation:

The trick you need to employ is that when the rock hits the ground, the timer stops. So h must be taken as 0.

0 = - 16t^2 + 255            Set up the equation

- 255 = - 16t^2                Divide by -16

15.9375 = t^2                  Switch

t^2 = 15.9375                   Take the square root of both sides.

sqrt(t^2) = sqrt(15.9375)

t = 3.992 seconds

The closest answer is B

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75