Find three consecutive whose sum 237

78 79 80

Step-by-step explanation:

Let the smallest number = x

Let the next number = x + 1

Let the largest number = x + 2

x + x + 1 + x + 2 = 237      Add together to get the equation

3x + 3 = 237                     Subtract 3 from both sides.

3x + 3 - 3 = 237 - 3          Combine the right

3x = 234                           Divide by 3

x = 234/3

x = 78

The smallest number is 78

The next number 79

The highest number is 80

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step-by-step explanation:

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