The sum of three consecutive odd numbers is 63. what is the smallest of these numbers?

The smallest number = 19

Step-by-step explanation:

We'll call X the smallest of those odd numbers

Then x + (x+2) + (x+4) = 63

X + X + 2 + X + 4 = 63

3X + 6 = 63

3X = 63 - 6 = 57

X = 57/3 = 19

The three consecutives odd numbers are 19, 21, 23

The sum = 19+21+23 = 63

Your answer : The smallest number = 19



the two may have that, even a breakdown is probably offered

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2