What is the equation of a line that passes through the point (0, 8) and is parallel to a line with a slope of 4/5 ?

y = 4/5 x +8

Step-by-step explanation:

point slope form of a line is

y-y1 = m(x-x1)

m = 4/5  (since it is parallel is has the same slope)

point (0,8)

y-8 = 4/5(x-0)

y-8 = 4/5 x

add 8 to each side

y = 4/5 x +8

this is now in slope intercept form

the y intercept is 8

the graph on the bottom right

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option