What are the solutions of the quadratic equation 0 = 4(x − 3)2 − 16?

x=1,5

Step-by-step explanation:

0 = 4(x − 3)^2 − 16

add 16 to each side

16 = 4(x − 3)^2 − 16+16

16 = 4(x − 3)^2

divide by 4

16/4 =  4/4(x − 3)^2

4 = (x-3)^2

take the square root of each side

+- sqrt (4) = sqrt( (x-3)^2)

+- 2 = (x-3)

add 3 to each side

3+- 2 = x

3+2 = x     and 3-2 = x

5=x       and 1=x

step-by-step explanation:

b and c

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?