The line that passes through 8,5 & 1,5

y = 5

Step-by-step explanation:

I assume you want the equation of the line.

First we find its slope:-

m = slope = rise / run = 5-5/8-5 = 0  which means that the line is horizontal

and runs through  the point where y = 5

Equation  of this line is y =- 5.

i dont know

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15