What is the value of c in the function x^2-7x+c to make it a perfect square trinomial?

c = 49/4

Step-by-step explanation:

The given expression is x^2 - 7x + c

This trinomial must be a perfect square.

Therefore, c must be a prefect square number.

So b^2 - 4ac = 0. That is discriminant must be equal to zero.

In the given expression a =1 and b = -7

Now plug in these values in the discriminant formula.

(-7)^2 - 4*1*c = 0

49 -4c = 0

4c = 49

c =  49/4

x^2 - 7x + 49/4 = (x - 7/2)^2

which is perfect square trinomial.

Thank you.

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