Can someone explain this to me . i dont know how to do it solve -5{3-2[1-4(3-2^2)]} by removing group symbols .

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Step-by-step explanation:

-5{3-2[1-4(3-2^2)]}

we work inside out

using PEMDAS

parenthesis, exponents, multiply and divide, add and subtract

the very most inside

(3-2^2)

do the exponents

3 - 4 = -1

replace where it was in the original equation

-5{3-2[1-4(-1)]}

take the next set of parenthesis (bracket are the same as parenthesis)

[1-4(-1)]

multiply

4*-1 = -4

1--4 = 1+4 = 5

replace  where it was in the original equation

-5{3-2[5]}

next set of parenthesis

{3-2[5]}

3 - 10 = -7

replace  where it was in the original equation

-5 {-7}

35

jwjwkwkwkkkdjebd b jdjejdndj he jenej

ratio is 2 : 9

the answer is three

13.5 : 3