Serena is making a large meatloaf that contains ground beef and ground pork. the beef is $3.50 per pound and the pork is $2.00 per pound. if she buys 0.75 pounds miri pork than beef and spends 15.25 in total , algebraically model this problem and determine how many pounds of each type of meat was bought.

Hi there! :)

Serena bought 0.75 pounds of pork and about 3.93 pounds of beef.

Step-by-step explanation:

Lets start by laying out the important information we know:

- Beef = $3.50/pound → 1 pound of beef = $3.50

- Pork = $2.00/pound → 1 pound of pork = $2.00

- Buys 0.75 pounds of pork → buys 0.75 of 1 pound of pork

- Buys x pounds of beef

- Spends $15.25 in total → 0.75 pounds of pork + x pounds of beef = $15.25

Once this is done, it's much easier to see what we are dealing with (when it's just a bunch of words it's a lot harder to understand).

Creating your algebraic equation:

Algebraically, your equation needs to be equal to the total amount that Serena spent on pork and beef.

She bought 0.75 of 1 pound of pork, which in other words means that she bought 0.75 of $2.00. The word "of" is the same thing as a multiplication sign. SO, all of this would translate into this: (0.75 × 2)

She then bought beef, but we don't know how much. What we can do is replace the "amount of pounds of beef she bought" with the letter "x". Remember, 1 pound of beef is $3.50. SO, all of this would translate into this: 3.50x

Your algebraic equation should look like this:

(0.75 × 2) + 3.50x = 15.25

Now all you need to do is solve this equation by isolating "x":

(0.75 × 2) + 3.50x = 15.25

1.5 + 3.50x = 15.25

Subtract 1.5 from each side of the equation → 15.25 - 1.5 = 13.75

3.50x = 13.75

Divide each side of the equation by 3.50 → 13.75 ÷ 3.50 = 3.92857143...

x ≈ 3.93

There you go! I really hope this helped, if there's anything just let me know! :)

x= cost per bracelet

number of bracelets * x + shipping charge = total cost

so

9x+9=72

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.