In parallelogram abcd, diagonals ac and bd intersect at point e, be =2x^2-3x, and de=x^2+10. what is bd? enter your answer in the box

70

Step-by-step explanation:

In parallelogram ABCD, diagonals AC and BD intersect at point E

E is the midpoint of BD

So BE = DE

Given: BE =2x^2-3x, and DE=x^2+10

BE = DE

(solve for x)

Subtract x^2 and 10 on both sides

Factor x^2-3x-10

(x-5)(x+2) = 0

x-5 =0  so x=5

x+2=0 so x=-2

Length x cannot be negative so we ignore x=-2

Lets plug in 5 for x  and find out BE  and DE

BE =

DE =

BD = BE + DE= 35+35 = 70

So BD = 70

i need a picure

step-by-step explanation: