In δabc shown below, line segment ab is congruent to line segment bc: triangle abc, where sides ab and cb are congruent given: line segment ab≅line segment bc prove: the base angles of an isosceles triangle are congruent. the two-column proof with missing statement proves the base angles of an isosceles triangle are congruent: statement reason 1. segment bd is an angle bisector of ∠abc. 1. by construction 2. ∠abd ≅ ∠cbd 2. definition of an angle bisector 3. 3. reflexive property 4. δabd ≅ δcbd 4. side-angle-side (sas) postulate 5. ∠bac ≅ ∠bca 5. cpctc which statement can be used to fill in the numbered blank space? line segment bd≅ line segment ac line segment bd≅ line segment bd line segment ac≅ line segment ac line segment ad≅ line segment dc

I've been working on this for a few days and i just don't understand, it's due in a few hours. you. the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α. part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part b suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case. part c now try a numerical problem. what is the direction of the vector w = < -1, 6 > ?