Iam trying to my 3rd grader to complete the tables to find how many ways each can be solved. here’s one. ! john has 42 model cars. he wants to put 3 cars on some shelves and 2 cars on other shelves. how many ways can he display his model cars? shelves with 3 cars: shelves with 2 cars: total cars: how do i solve this?

Shelves with 3 cars: 10

Shelves with 2 cars: 6

Total:42

Shelves with 3 cars: 6

Shelves with 2 cars: 12

Total:42

There are many ways to do this. So what I did was multiply 3 by a number like 10. Then I took the 2 and multiplied it  by 3. i added the numbers 30+6=36. that doesn't work so i tried 2 multiplied by 6. 30+12=42. Hope this helped a little. :D

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

the correct answer is the second option