If the equation of the line y = -5x + 8 is changed to y = -125x + 8, how does the graph change?

The original line . . . Y = -5x + 8

-- The slope of the line is -5 .  It slopes down, 5 steps down for every step forward.

-- The y-intercept is 8 .  The line crosses the y-axis at the point where y=8 .

= = = = =

The new line . . . Y = -125x + 8

-- The slope of the line is -125 .  It slopes down, 125 steps down for every step forward.  That's 25 times as steep as the original line.

-- The y-intercept is 8 .  The line crosses the y-axis at the point where y=8 .  That's the same as the original line.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

step-by-step explanation: