Mathematics, 30.06.2019 20:00 haleynicole351ovewbg
Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic feet. what is the area of its bottom floor? include equations or inequalities related.
Answers: 1
![\sqrt[3]{3140^2\pi}\approx 146.41\ ft^2](/tpl/images/0036/0641/4fe9f.png)
and V=1570 cubic feet, then![1570=\pi r^2\cdot \dfrac{r}{2},\\ \\1570=\dfrac{\pi r^3}{2},\\ \\r^3=\dfrac{3140}{\pi},\\ \\r=\sqrt[3]{\dfrac{3140}{\pi}}\ ft.](/tpl/images/0036/0641/99172.png)
![A_{floor}=\pi r^2=\pi\cdot \left(\sqrt[3]{\dfrac{3140}{\pi}}\right)^2= \sqrt[3]{3140^2\pi}\approx 146.41\ ft^2.](/tpl/images/0036/0641/45b23.png)
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Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, an...
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