Write the equation of the ellipse with center (4,2), vertex (9,2), and focus (4+2sqrt5,2)

Answer : option B

Given: center (4,2), vertex (9,2), and focus (4+2sqrt5,2)

The distance between vertex and center is 9-4 = 5

Center is (h,k) so h= 4  and k =2

focus is (h+c,k)

From the given focus (4+2sqrt5,2), c= 2sqrt(5)

Standard form of equation is

h= 4, k=2, a=5, c=2sqrt(5), we need to find out b

b^2 = 5

plug in all the values

Option B is correct

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube