Aship left port a with a speed of 40 mph. in 1 1/4 of an hour, a second ship left the port with a speed of 60 mph. in how many hours and at what distance from port a will the second ship catch up with the first one?

The matter explained that the first ship had a speed of 40 mph when leaving the port and within 1 1/4 hours the second ship followed with a speed of 60 mph. And the question is when will the first and the second ship meet and in how long?

To calculate the distance from the port and when the second ship follows when the first, the first step that we have to calculate is, calculate the distance of the first ship that has departed first in 1 1/4 hours we can calculate using 1.25 x 40 = 50 miles.

The distance of the first ship from the port is known, the next step is to calculate the time interval if the first and second ships will meet. We can calculate it by dividing the distance of the first ship with the port and the difference in speed of the first ship and the second ship. 50: 20 = 2.5 hours

The time interval between the first ship and the second ship meets is known, the next step is to calculate the distance of ship 1 and ship 2 will meet. We can calculate it by multiplying the speed of the second ship with the time the first ship and the second ship will meet. 60 x 2.5 = 150 miles.

So the first ship and the second ship will meet at a distance of 150 miles in 2.5 hours.

Comparison is comparing 2 or more of the same magnitude and shown with the simplest value.

The comparison can be divided into:

It is important to know that comparisons must:

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Class: Middle School

Subject: Mathematics

Keyword: How to calculate the comparison.

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.

answer: graph 2

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