Which of the following is tge first four terms of the sequence a n=3n+5?

c

to generate the first four terms, substitute n = 1, 2, 3, 4 into the formula

= (3 × 1) + 5 = 3 + 5 = 8

= (3 × 2 ) + 5 = 6 + 5 = 11

= (3 × 3) + 5 = 9 + 5 = 14

= (3 × 4) + 5 = 12 + 5 = 17

the first four terms are 8, 11, 14, 17 → c

i need a picure

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.