The perimeter of a rectangle is 88m if the width were doubled and the length were increased by 12m, the perimeter would be 152m what is the length of the original rectangle

The answer is: The length of the original rectangle is 24 meters.

Explanation:

1. The perimeter of a rectangle is:

Where is the length and is the width

2. The perimeter of the original rectangle is 88 meters, therefore:

(First equation)

3.  The width were doubled, the length were increased by 12 meters and the new perimeter is 152 meters. Therefore:

(Second equation)

4. As you can see, you have a system of equations:

5. You can solve it by applying the Elimination Method. Multiply the first equation by -1, add both equations and solve for :

6. Now, you can calculate the lenght by substituying the width into one of the original equations:

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are