Line cd passes through points c(3, –5) and d(6, 0). what is the equation of line cd in standard form? 1. 5x + 3y = 18 2. 5x – 3y = 30 3. 5x – y = 30 4. 5x + y = 18

The equation of the line CD expressed in standard form which passes through the points C(3, –5) and D(6, 0) is;. 5x - 3y = 30

The equation of a straight line can be determined by first determining the slope of the line if two points are given on the straight line.

m = 5/3.

The equation of the line can then be gotten from the slope and a pair of ordinates as follows;

5x - 3y = 30.

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Line CD is Passing through the Points (3 , -5) and (6 , 0)

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

here x₁ = 3 and x₂ = 6 and y₁ = -5 and y₂ = 0

We know that the form of line passing through point (x₀ , y₀) and having slope m is : y - y₀ = m(x - x₀)

Here the line passes through the point (3 , -5) and (6 , 0)

We can take any one point of the both

let us take (3 , -5)

x₀ = 3 and y₀ = -5 and we found

Equation of the line :

⇒ 3y + 15 = 5x - 15

⇒ 5x - 3y = 30

Option 2 is the Answer