Arectangular two-story horse barn is being designed for a farm. the upper floor will be used for storing hay, and the lower floor will have horse stalls that extend 6 feet from both of the longer walls. the barn's length is twice the barn's width, and the lower floor's ceiling height is 8 feet less than the barn's width. what should the dimensions of the lower floor be if the space not used for stalls is to have a volume of 3,840 cubic feet?

Let the width of the barn be = x feet

So length of the barn = 2x

Height of the barn = x-8

As the stalls are 6 feet longer from both ends hence, we have to find the area with width as x-12 feet

Volume of the space is = 3840 cubic feet

Hence, equation is :

Solving this we get

This gives x=20 and x= ±

Hence, neglecting the square root value we get x = 20 feet

Hence, the width is = x-12 = 20 - 12 = 8 feet

Length is = 2x = 2*20 = 40 feet

Height is = x-8 = 20 - 8 =12 feet

And we can cross check this by multiplying all the three dimensions to get 3840 cubic feet

cubic feet.

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

congruent segments

step-by-step explanation: