The length of a rectangular parking lot at the airport is 2/3 mile. if the area is 1/2 square mile, what is the width of the parking lot?

3/4 mile

Area is the product of length and width. Put the given values into that formula and solve for width.

... A = L·W

... (1/2 mi²) = (2/3 mi)·W

... (1/2 mi²)/(2/3 mi) = W = (1/2)·(3/2) mi

... W = 3/4 mi

i need more information

step-by-step explanation:

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.