The sum of three consecutive odd numbers is 69. what is the smallest of the three numbers?

21

Step-by-step explanation:

Let the smallest of the numbers be N

The other two numbers (consecutive) would be written as (n + 2), (n + 4)

Expressing these as an equation gives : (n) + (n+2) + (n+4) = 69

opening the bracket and collecting like terms, we have:

n+n+n+2+4=69

3n + 6 = 69

3n = 69 - 6

3n = 63

Dividing both sides by 3 or making n the subject formular, we get:

n = 63/3

n = 21.

Note, the other numbers are: 21, 23, and 25

They are all odd numbers

Their sum equals to 69

6/20

step-by-step explanation: