Write an equation of a line in slope intercept form to the given line and pass through the given pointy = 4x + 6 ; (4,8)i'm not sure as to how to start or what steps to use

Slope intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (when x = 0)

I'm assuming that the equation of a line is parallel to the given line.

When lines are parallel, they have the same slope.

The given line's slope is 4, so the parallel line's slope is also 4

y = mx + b

y = 4x + b

To find b, you plug in the point (4,8) into the equation.

y = 4x + b

8 = 4(4) + b

8 = 16 + b  Subtract 16 on both sides

-8 = b

Your equation is:

y = 4x - 8

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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